Problem 1 — Visual explainer (undergrad) ======================================== Problem statement --------------- If $A\subseteq \{1,\ldots,N\}$ with $\lvert A\rvert=n$ is such that the subset sums $\sum_{a\in S}a$ are distinct for all $S\subseteq A$ then\[N \gg 2^{n}.\] Picture ------- Pick A = {a1, a2, ..., an} All subsets S ⊆ A (there are 2^n) Each subset gives a sum sum(S) S sum(S) -------- ------ ∅ 0 {a1} a1 {a2} a2 {a1,a2} a1+a2 ... Conjecture / Task: what to look at ------------------------ - Restate the problem as: given the constraint, what asymptotic bound or structure must follow? - Use the comments as benchmarks (best known bounds / constructions). Context ------- Area hint: additive combinatorics / additive number theory. Notation (if it appears above) ----------------------------- - `\gg` / `>>` means "at least a constant times" (for large parameters). Benchmarks / known results (from comments) ---------------------------------------- - The powers of $2$ show that $2^n$ would be best possible here. - The trivial lower bound is $N \gg 2^{n}/n$, since all $2^n$ distinct subset sums must lie in $[0,Nn)$. - Erd\H{o}s and Moser proved\[ N\geq (\tfrac{1}{4}-o(1))\frac{2^n}{\sqrt{n}}.\](In Erd\H{o}s offered \$100 for any improvement of the constant $1/4$ here.) A number of improvements of the constant have been given (see for a history), with the current record $\sqrt{2/\pi}$ first proved in unpublished work of Elkies and Gleason. - Two proofs achieving this constant are provided by Dubroff, Fox, and Xu, who in fact prove the exact bound $N\geq \binom{n}{\lfloor n/2\rfloor}$.